Question

An ideal refrigerator does 150 J of work to remove 560 J as heat from its cold compartment. What is the refrigerator’s coefficient of performance?

Solution

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Answered 4 months ago
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Given:

  • Work: W=150 JW = 150 \mathrm{~J};
  • Heat: QL=560 JQ_\text L = 560 \mathrm{~J};

Required:

a) The efficiency of a refrigerator KK;

b) Amount of heat exhausted per cycle QexhaustedQ_\text{exhausted};

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