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Question

An object, which is at the origin at time $t=0$, has initial velocity $\overrightarrow{\mathbf{v}}_0=(-14.0 \hat{\mathbf{i}}-7.0 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}$ and constant acceleration $\overrightarrow{\mathbf{a}}=(6.0 \hat{\mathbf{i}}+3.0 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}^2$. Determine the position $\overrightarrow{\mathbf{r}}$ where the object comes to rest (momentarily).

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 8The knowns are:

- $\vec{\bm{v}}_0 = -14.0\;\mathrm{m/s}\ \bm{\hat{i}} - 7.0\;\mathrm{m/s}\ \bm{\hat{j}}$
- $\vec{\bm{a}} = (6.0\ \bm{\hat{i}} + 3.0\ \hat{\bm{j}})\ \mathrm{m/s²}$

Our goal is to calculate the position vector at the moment when the particle comes to rest.

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