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An octahedral complex with three different ligands (A, B, and CC ) can have formulas with three different ratios of the ligands: [MA4BC]n+,\left[\mathrm{MA}_4 \mathrm{BC}\right]^{n+}, \quad such as [Co(NH3)4(H2O)Cl]2+\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4\left(\mathrm{H}_2 \mathrm{O}\right) \mathrm{Cl}\right]^{2+} [MA3 B2C]n+\left[\mathrm{MA}_3 \mathrm{~B}_2 \mathrm{C}\right]^{n+}, such as [Cr(H2O)3Br2Cl]\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_3 \mathrm{Br}_2 \mathrm{Cl}\right] [MA2 B2C2]n+\left[\mathrm{MA}_2 \mathrm{~B}_2 \mathrm{C}_2\right]^{n+}, such as [Cr(NH3)2(H2O)2Br2]+\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_2\left(\mathrm{H}_2 \mathrm{O}\right)_2 \mathrm{Br}_2\right]^{+} For each example, give the name, state the type(s) of isomerism present, and draw all isomers.

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We are given three octahedral complexes we need to name them, state the type of isomerism and draw all isomers.

First example is:

[MA4BC]n+ as [Co(NH3)4(H2O)Cl]2+\mathrm{[MA_4BC]^{n+}}\text{ as }\mathrm{[Co(NH_3)_4(H_2O)Cl]^{2+}}

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