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An RC series circuit consists of an AC source, a 33.0μF33.0 - \mu \text F capacitor, and a 30.0-Ω\Omega resistor. If the source emf is given by ε=εmaxsin(ωt)\varepsilon = \varepsilon_ { max } \sin ( \omega t ), where Emax=180.0VE _ { \max } = 180.0 \mathrm { V } and ω=20.0s1\omega = 20.0 \mathrm { s } ^ { - 1 }, what is the current amplitude?

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In the exercise we have a circuit with a capacitor and a resistor in series and we need to find the current amplitude II with the next information:

  • C=6.00mFC=6.00\,\text{mF}, Capacitance of the capacitor,

  • R=20.0ΩR=20.0\,\Omega, Resistance of the resistor,

  • ξ=ξmaxsin(ωt)\xi=\xi_{\text{max}}\sin(\omega t), emf of the AC source,

  • ξmax=5.00V\xi_{\text{max}}=5.00\,\text{V}, Maximum value of emf,

  • ω=10.0s1\omega=10.0\,\text{s}^{-1}, Angular frequency.

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