## Related questions with answers

Question

An x-ray beam of wavelength A undergoes first-order reflection (Bragg law diffraction) from a crystal when its angle of incidence to a crystal face is

$23 ^ { \circ }$

, and an x-ray beam of wavelength 61 pm undergoes third-order reflection when its angle of incidence to that face is

$60 ^ { \circ }$

. Assuming that the two beams reflect from the same family of reflecting planes, find (a) the interplanar spacing and (b) the wavelength A.

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 3For Bragg diffraction we know that

$2d\sin\theta=m\lambda$

So the interplaner spacing $d$ is given by

$d=\frac{m\lambda}{2\sin\theta}=\frac{3\times(61\times 10^{-12})}{2\times \sin(60\text{\textdegree})}=1.05\times10^{-10}\ \mathrm{m}$

So the interplanner spacing is 1.05 $\text{\AA}$.

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