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Question

Answer for the sequence vv defined by vn=n!+2v_n=n!+2, n1n\geq 1. Find i=14vi\sum_{i=1}^4 v_i.

Solution

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Given:

vn=n!+2,n1v_n=n!+2, \:\:\:\:\: n\geq 1

Evaluate at n=1,2,3,4n=1,2,3,4:

v1=1!+2=1+2=1+2=3v2=2!+2=21+2=2+2=4v3=3!+2=321+2=6+2=8v4=4!+2=4321+2=24+2=26\begin{align*} v_1&=1!+2=1+2=1+2=3 \\ v_2&=2!+2=2\cdot 1+2=2+2=4 \\ v_3&=3!+2=3\cdot 2\cdot 1+2=6+2=8 \\ v_4&=4!+2=4\cdot 3\cdot 2\cdot 1+2=24+2=26 \end{align*}

Let us add all these terms:

i=14vi=v1+v2+v3+v4=3+4+8+26=41\sum_{i=1}^4 v_i=v_1+v_2+v_3+v_4=3+4+8+26=41

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