## Related questions with answers

Approximately how many oxygen molecules arrive each second at the mitochondrion of an active person with a mass of $84 \mathrm{~kg}$ ? The following data are available: Oxygen consumption is about $40 . \mathrm{mL}$ of $\mathrm{O}_2$ per minute per kilogram of body weight, measured at $T=300 .\ \mathrm{K}$ and $P=1.00 \mathrm{~atm}$. In an adult there are about $1.6 \times 10^{10}$ cells per kg body mass. Each cell contains about 800 . mitochondria.

Solutions

VerifiedThe aim of this task is to determine the amount of oxygen $(\mathrm{O}_2)$ per second arriving at each mitochondrion of an $84\mathrm{~kg}$ person.

For this, we can assume the following data: the consumption $\mathrm{O}_2$ of a person is $40\mathrm{~[{mL}/{min]\cdot kg}}$ at a temperature $T=300\mathrm {~K}$ and press $1.00\mathrm{~atm}$.

There are $1.6\times10^{10}$ cells per $\mathrm{kg}$ body mass and each cell contains $800$ mitochondria.

*How can we use the ideal gas law to calculate the amount of substance in a gas?*

This man consumes about 40 mL / minute kilogram , and his mass is $84$ kg

so that

$\begin{align*} \text{Oxygen consumption}&=40\dfrac{\text{mL}}{\text{minute kilogram}}\times 84\text{ kg}\times \dfrac{1\text{minute}}{60\text{ second}}\\ &=56 \text{ mL s}^{-1}\\ &\boxed{=.056 \text{ L s}^{-1}} \end{align*}$

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