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# Approximately how many oxygen molecules arrive each second at the mitochondrion of an active person with a mass of $84 \mathrm{~kg}$ ? The following data are available: Oxygen consumption is about $40 . \mathrm{mL}$ of $\mathrm{O}_2$ per minute per kilogram of body weight, measured at $T=300 .\ \mathrm{K}$ and $P=1.00 \mathrm{~atm}$. In an adult there are about $1.6 \times 10^{10}$ cells per kg body mass. Each cell contains about 800 . mitochondria.

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The aim of this task is to determine the amount of oxygen $(\mathrm{O}_2)$ per second arriving at each mitochondrion of an $84\mathrm{~kg}$ person.

For this, we can assume the following data: the consumption $\mathrm{O}_2$ of a person is $40\mathrm{~[{mL}/{min]\cdot kg}}$ at a temperature $T=300\mathrm {~K}$ and press $1.00\mathrm{~atm}$.

There are $1.6\times10^{10}$ cells per $\mathrm{kg}$ body mass and each cell contains $800$ mitochondria.

How can we use the ideal gas law to calculate the amount of substance in a gas?

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