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Approximately how many oxygen molecules arrive each second at the mitochondrion of an active person with a mass of 84 kg84 \mathrm{~kg} ? The following data are available: Oxygen consumption is about 40.mL40 . \mathrm{mL} of O2\mathrm{O}_2 per minute per kilogram of body weight, measured at T=300. KT=300 .\ \mathrm{K} and P=1.00 atmP=1.00 \mathrm{~atm}. In an adult there are about 1.6×10101.6 \times 10^{10} cells per kg body mass. Each cell contains about 800 . mitochondria.

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The aim of this task is to determine the amount of oxygen (O2)(\mathrm{O}_2) per second arriving at each mitochondrion of an 84 kg84\mathrm{~kg} person.

For this, we can assume the following data: the consumption O2\mathrm{O}_2 of a person is 40 [mL/min]kg40\mathrm{~[{mL}/{min]\cdot kg}} at a temperature T=300 KT=300\mathrm {~K} and press 1.00 atm1.00\mathrm{~atm}.

There are 1.6×10101.6\times10^{10} cells per kg\mathrm{kg} body mass and each cell contains 800800 mitochondria.

How can we use the ideal gas law to calculate the amount of substance in a gas?

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