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Question

As a prank, someone has balanced a pumpkin at the highest point of a grain silo. The silo is topped with a hemispherical cap that is frictionless when wet. The line from the center of curvature of the cap to the pumpkin makes an angle θi=0\theta_{i}=0^{\circ} with the vertical. While you happen to be standing nearby in the middle of a rainy night, a breath of wind makes the pumpkin start sliding downward from rest. It loses contact with the cap when the line from the center of the hemisphere to the pumpkin makes a certain angle with the vertical. What is this angle?

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Answered 1 year ago
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Given:\textbf{Given:}

\color{#4257b2}\bullet \bullet vi=0v_i=0 m/s

\color{#4257b2}\bullet \bullet yi=Ry_i=R

\color{#4257b2}\bullet \bullet yf=hy_f=h

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