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Question

As mentioned in Exercise 4.52, a July 21 survey on www.HuffingtonPost.com asked people to choose their favorite junk food from a list of choices. Considering that there were 4801 female respondents and 3201 male respondents, even though the findings were not broken down by gender, let's assume that the following table represents the results for the 8002 respondents.

 Favorite Junk Food  Female  Male  Chocolate 1518531 Sugary candy 218127 Ice cream 685586 Fast food 312463 Cookies 431219 Chips 458649 Cake 387103 Pizza 792523\begin{array}{lcc} \hline \text { Favorite Junk Food } & \text { Female } & \text { Male } \\ \hline \text { Chocolate } & 1518 & 531 \\ \text { Sugary candy } & 218 & 127 \\ \text { Ice cream } & 685 & 586 \\ \text { Fast food } & 312 & 463 \\ \text { Cookies } & 431 & 219 \\ \text { Chips } & 458 & 649 \\ \text { Cake } & 387 & 103 \\ \text { Pizza } & 792 & 523 \\ \hline \end{array}

Let's say that one respondent is chosen at random from this sample of 8002 people. Identify the probabilities for each. a. The likelihood that a feminine event will involve chocolate. b. Probability of the union of events male and cake.

Solution

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Answered 1 year ago
Answered 1 year ago
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In order to solve this task, we need to calculate the probability using the formula

P(A or B)=P(A)+P(B)P(A and B)P(A \text{ or }B)=P(A)+P(B)-P(A\text{ and } B)

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