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Question

As you know, when a course ends, students start to forget the material they have learned. One model (called the Ebbinghaus model) assumes that the rate at which a student forgets material is proportional to the difference between the material currently remembered and some positive constant, a.

Solve the differential equation.

Solution

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Answered 2 years ago
Answered 2 years ago
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Lets solve the equation

dydt=k(ya)dyya=kdtln(ya)=kt+Cya=Cekty(t)=a+Cekt\begin{align*} \dfrac{dy}{dt}&=-k(y-a) \\ \\ \dfrac{dy}{y-a}&=-kdt\tag{integrate both sides}\\ \ln (y-a)&=-kt+C\\ y-a&=Ce^{-kt}\\ y(t)&=a+Ce^{-kt}\\ \end{align*}

For t=0t=0, y=1y=1.

1a=Cy=a+(1a)ekt\begin{align*} 1-a&=C\\ y&=a+(1-a)e^{-kt} \end{align*}

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