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Question

Assume that the outside temperature varies as

T(t)=15+5 sin (π\pi t / 12)

where t=0t=0 is 12 noon. A house is heated to 2525^{\circ}C at t=0 and after that, its temperature y(t) varies according to Newton's Law of Cooling :

dy/dt=-0.1(y(t)-T(t))

Use Earlier Exercise to solve for y(t).

Solution

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We are given:

T(t)=15+5sin(πt/12)T(t)=15+5\sin (\pi t/12)

y0=25y_0=25

dydt=0.1(y(t)T(t))\dfrac{dy}{dt}=-0.1(y(t)-T(t))

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