## Related questions with answers

Question

Assume that the outside temperature varies as

T(t)=15+5 sin ($\pi$ t / 12)

where $t=0$ is 12 noon. A house is heated to $25^{\circ}$C at t=0 and after that, its temperature y(t) varies according to Newton's Law of Cooling :

dy/dt=-0.1(y(t)-T(t))

Use Earlier Exercise to solve for y(t).

Solution

VerifiedStep 1

1 of 6We are given:

$T(t)=15+5\sin (\pi t/12)$

$y_0=25$

$\dfrac{dy}{dt}=-0.1(y(t)-T(t))$

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