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At a particular temperature, a 2.00-L flask at equilibrium contains

2.80×104 mole of N2,2.50×105 mole of O2, and 2.00×102 mole of N2O2.80 \times 10 ^ { - 4 } \text { mole of } N _ { 2 }, 2.50 \times 10 ^ { - 5 } \text { mole of } \mathrm { O } _ { 2 } , \\ \text { and } 2.00 \times 10 ^ { - 2 } \text { mole of } \mathrm { N } _ { 2 } \mathrm { O }

Calculate K at this temperature for the reaction

2N2(g)+O2(g)2N2O(g)2 \mathrm { N } _ { 2 } ( g ) + \mathrm { O } _ { 2 } ( g ) \rightleftharpoons 2 \mathrm { N } _ { 2 } \mathrm { O } ( g )

If

[N2]=2.00×104M,[N2O]=0.200M,and[O2]=0.00245M\left[ \mathrm { N } _ { 2 } \right] = 2.00 \times 10 ^ { - 4 } \mathrm { M } , \left[ \mathrm { N } _ { 2 } \mathrm { O } \right] = 0.200 \mathrm { M } , \mathrm { and } \left[ \mathrm { O } _ { 2 } \right] =0.00245 M

does this represent a system at equilibrium?

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