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At f = 100 MHz, show that silver $\left(\sigma=6.1 \times 10^{7} \mathrm{S} / \mathrm{m}, \mu_{r}=1, \varepsilon_{r}=1\right)$ is a good conductor, while rubber $\left(\sigma=10^{15} \mathrm{S} / \mathrm{m}, \mu_{r}=1, \varepsilon_{r}=3.1\right)$ is a good insulator.
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Answered 1 year ago
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1 of 6We are given a frequency of $f=100 ~\mathrm{MHz}$, and the parameters of two materials:

Silver $(\sigma = 6.1 \cdot 10^7 \mathrm{~\frac{S}{m}}, \epsilon_r = 1, \mu_r = 1)$

Rubber $(\sigma = \cdot 10^{15} \mathrm{~\frac{S}{m}}, \epsilon_r = 1, \mu_r = 3.1)$
We must show that silver is a good conductor at this frequency, and that rubber is a good insulator at this frequency.
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