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# At its peak, a tornado is 60.0 m in diameter and carries 500 km/h winds. What is its angular velocity in revolutions per second?

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Answered 7 months ago
Answered 7 months ago
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$\textbf{Knowns}$

\normalsize
We know that the relation between angular velocity $\color{#c34632}\omega$ and tangential velocity $\color{#c34632}v$ is given by:


$\begin{gather*} \omega = \dfrac{v}{r}\tag{1} \end{gather*}$

Where $\color{#c34632}r$ is the radius of curvature.


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