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Consider a random variable X of the continuous type with cdf F(x)F(x) and pdf f(x).f(x). The hazard rate (or failure rate or force of mortality) is defined by r(x)=limΔ0P(xX<x+ΔXx)Δ(3.3.8)r(x)=\lim _{\Delta \rightarrow 0} \frac{P(x \leq X<x+\Delta | X \geq x)}{\Delta} \quad (3.3.8) In the case that X represents the failure time of an item, the above conditional probability represents the failure of an item in the interval [x,x+Δ][x, x+\Delta] given that it has survived until time x. Viewed this way, r(x) is the rate of instantaneous failure at time x>0.x>0. (a) Show that r(x)=f(x)/(1F(x)).r(x)=f(x) /(1-F(x)). (b) If r(x)=c,r(x)=c, where c is a positive constant, show that the underlying distribution is exponential. Hence, exponential distributions have constant failure rates over all time. (c) If r(x)=cxb;r(x)=c x^{b} ; where c and b are positive constants, show that X has a Weibull distribution; i.e.,

f(x)={cxbexp{cxb+1b+1}0<x<0 elsewhere (3.3.9)f(x)=\left\{\begin{array}{ll}c x^{b} \exp \left\{-\frac{c x^{b+1}}{b+1}\right\} & 0<x<\infty \\ 0 & \text { elsewhere }\end{array}\right. \quad (3.3 .9)

(d) If r(x)=cebx,r(x)=c e^{b x}, where c and b are positive constants, show that X has a Gompertz cdf given by

F(x)={1exp{cb(1ebx)}0<x<0 elsewhere (3.3.10)F(x)=\left\{\begin{array}{ll}1-\exp \left\{\frac{c}{b}\left(1-e^{b x}\right)\right\} & 0<x<\infty \\ 0 & \text { elsewhere }\end{array}\right. \quad (3.3.10)

This is frequently used by actuaries as a distribution of "length of life."

Question

At some point in their lives most people will suffer from at least one onset of low back pain. This disorder can trigger excruciating pain and temporary disability, but its causes are hard to diagnose. It is well known that low back pain alters motor trunk patterns; thus it is of interest to study the causes for these alterations and their extent. Due to the different possible causes of this type of pain, a "control" group of people is hard to obtain for laboratory studies. However, pain can be stimulated in healthy people and muscle movement ranges can be compared. Controlled back pain can be induced by injecting saline solution directly into related muscles or ligaments. The transfer function from infusion rate to pain response was obtained experimentally by injecting a 5% saline solution at six different infusion rates over a period of 12 minutes. Subjects verbally rated their pain every 15 seconds on a scale from 0 to 10, with 0 indicating no pain and 10 unbearable pain. Several trials were averaged and the data was fitted to the following transfer function:

G(s)=9.72×108(s+0.0001)(s+0.009)2(s2+0.018s+0.0001)G(s)=\frac{9.72 \times 10^{-8}(s+0.0001)}{(s+0.009)^{2}\left(s^{2}+0.018 s+0.0001\right)}

For experimentation, it is desired to build an automatic dispensing system to make the pain level constant as shown in figure below. It follows that ideally the injection system transfer function has to be

M(s)=1G(s)M(s)=\frac{1}{G(s)}

to obtain an overall transfer function M(s)G(s) \approx 1. However, for implementation purposes M(s) must have at least one more pole than zeros. Find a suitable transfer function, M(s) by inverting G(s) and adding poles that are far from the imaginary axis.

Infusion PumpHuman responseConstantConstantInfusionM(s)G(s)backRatepain\scriptscriptstyle \begin{matrix} && \text{Infusion Pump} && \text{Human response}\\ \text{Constant} &&&&&& \text{Constant}\\ \text{Infusion} & \mathrm{\rightarrow} & \text{M(s)} & \mathrm{\rightarrow} & \text{G(s)} & \mathrm{\rightarrow} & \text{back}\\ \text{Rate} &&&&&& \text{pain}\\ \end{matrix}

Solution

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When G(s) is inverted to obtain M(s), the numerator degree is four and the denominator degree is one. Thus M(s) must have at least four new poles added to the denominator so that the denominator degree is more than the numerator. The new poles need to be placed at least 10 times the poles and zeros of G(s).

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