Question

At the surface of the Earth, the Sun delivers an estimated 1.00 kW/m21.00 \mathrm{~kW} / \mathrm{m}^2 of energy. Suppose sunlight hits a 10.0 m10.0 \mathrm{~m} by 30.0 m30.0 \mathrm{~m} roof at an angle of 90.090.0^{\circ}. a) Estimate the total power incident on the roof. b) Find the radiation pressure on the roof.

Solution

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Answered 1 year ago
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We will use equation for power delivered to surface in which intensity of electromagnetic waves is known do determine power delivered to roof. We will use equation for radiation pressure to determine radiation pressure on the roof.

We are given:

  • intensity of Sun radiation on the roof I=1000 Wm2I=1000 \mathrm{~\dfrac{W}{m^2}}
  • width of the roof w=10 mw=10 \mathrm{~m}
  • length of the roof l=30 ml=30 \mathrm{~m}
  • Sunlight is perpendicular to the surface of the roof

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