Question
At winter design conditions, a house is projected to lose heat rate of 60,000 Btu/h. The internal heat gain from people, lights, and appliances is estimated to be 6000 Btu/h. if this house is to be heated by electric resistance heaters, determine the required rated power of these heaters in kW to maintain the house at constant temperature.
Solutions
VerifiedSolution A
Solution B
Step 1
1 of 2(60,000 Btu/h) - (6,000 Btu/h) = 54,000 Btu/h
1 kW = 3412.14 Btu/h
54,000/3412.14 = 15.8 kW
Answered 9 months ago
Step 1
1 of 5
- - heat gain rate
- - heat lost rate
- - power of heaters
Create an account to view solutions
By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Create an account to view solutions
By signing up, you accept Quizlet's Terms of Service and Privacy Policy
Recommended textbook solutions

Fundamentals of Electric Circuits
6th Edition•ISBN: 9780078028229 (9 more)Charles Alexander, Matthew Sadiku2,120 solutions

Physics for Scientists and Engineers: A Strategic Approach with Modern Physics
4th Edition•ISBN: 9780133942651 (8 more)Randall D. Knight3,508 solutions

Advanced Engineering Mathematics
10th Edition•ISBN: 9780470458365 (6 more)Erwin Kreyszig4,134 solutions

Thermodynamics: An Engineering Approach
9th Edition•ISBN: 9781260048667 (1 more)Michael A. Boles, Yunus A. Cengel2,611 solutions