Question

Balance each of the following oxidation-reduction reactions. For each, indicate which substance is being oxidized and which is being reduced.
a. Co(s)+Br2(l)CoBr3(s)\mathrm{Co}(s)+\mathrm{Br}_2(l) \rightarrow \mathrm{CoBr}_3(s)

Solution

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To solve this problem we use rules for balancing equations that say: first start with the most complicated molecule and then proceed element by element and use appropriate coefficient to have the same number of the element on both sides of the arrow.

Coefficients used are the smallest integers that balance the number of each element on both side of the arrow.

Unbalanced equation is:

Co(s)+Br2(l)CoBr3(s)\mathrm{Co_ { ( s ) } + Br _ { 2 ( l ) } \rightarrow CoBr _ {3 ( s )}}

The most complicated compound is CoBr3\mathrm{CoBr_3}.

The easiest way to solve this problem is to use coefficient 2 before CoBr3\mathrm{CoBr_3}.

If we use coefficient 2 before CoBr3\mathrm{CoBr_3}, the number of Co atoms on the right side of the reaction arrow is 2.

To balance number of Co atoms on both sides of the reaction arrow we must use coefficient 2 before Co\mathrm{Co}

2Co(s)+Br2(l)2CoBr3(s)\mathrm{2Co_ { ( s ) } + Br _ { 2 ( l ) } \rightarrow 2CoBr _ {3 ( s )}}

The number of Br\mathrm{Br} atoms on the right side of the reaction arrow is 6.

To balance a number of Br\mathrm{Br} atoms on both sides of the reaction arrow we must use coefficient 3 before Br2\mathrm{Br_2}.

Balanced equation:

2Co(s)+3Br2(l)2CoBr3(s)\mathrm{2Co_ { ( s ) } + 3Br _ { 2 ( l ) } \rightarrow 2CoBr _ {3 ( s )}}

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