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Uranium-235 undergoes a series of a-particle and -particle productions to end up as lead-207. How many particles and particles are produced in the complete decay series?
Solution
VerifiedForm a nuclear equation of uranium-235 decaying to lead-207 including the -particles, and -particles
We know that -particles can change the mass number, thus we balance the mass number first
Subtract the mass number of lead-207 from the mass number of uranium-235 and divide it by the mass number of helium which has the same mass number of an -particle
An -particle has an atomic number of 2, we have 7 -particles , thus we have a total atomic number of 14 added to the atomic number of lead-207, exceeds the atomic number of uranium-235 by 4
A -particle has an atomic number of -1, thus to balance the reaction, we need 4 -particles
Thus, the balanced nuclear reaction of U-235 decaying to lead-207 by a series of and decay is as follows:
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