## Related questions with answers

Question

A manufacturer of lightbulbs wants to produce bulbs that last about 700 hours but, of course, some bulbs burn out faster than others. Let $F ( t )$ be the fraction of the company's bulbs that burn out before t hours, so $F ( t )$ always lies between 0 and 1. What is the meaning of the derivative $r ( t ) = F' ( t )$ ?

Solution

VerifiedStep 1

1 of 2$r(t) = F'(t)$

This is the rate at which $F(t)$ is changing at time $t$. The rate at which bulbs are burning out at $t$ hours.

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