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A manufacturer of lightbulbs wants to produce bulbs that last about 700 hours but, of course, some bulbs burn out faster than others. Let F(t)F ( t ) be the fraction of the company's bulbs that burn out before t hours, so F(t)F ( t ) always lies between 0 and 1. What is the meaning of the derivative r(t)=F(t)r ( t ) = F' ( t ) ?

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r(t)=F(t)r(t) = F'(t)

This is the rate at which F(t)F(t) is changing at time tt. The rate at which bulbs are burning out at tt hours.

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