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Question

Both situations have the same expected value. Find the missing information. Situation 1: Paul hits a dart target worth 15 points 45% of the time. Situation 2: He hits a dart target worth 10 points x% of the time.

Solution

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Use the expected value formula:

E(x)=x1P(x1)+x2P(x2)+x3P(x3)++xnP(xn)(1)E(x)=x_1P(x_1)+ x_2P(x_2)+ x_3P(x_3)+\cdots+ x_nP(x_n)\color{white}{\tag{1}}

Since the expected values are the same, then we can write:

E1=E2E_1=E_2

1545100=10x10015\cdot \dfrac{45}{100}=10\cdot \dfrac{x}{100}

Mutliply both sides by 100:

1545=10x15\cdot 45=10x

675=10x675=10x

67.5=x67.5=x

The missing information is 67.5%\color{#c34632}{67.5\%}.

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