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Question

Calculate the derivatives of the functions. f(x)=[(6.4x1)2+(5.4x2)3]2f(x)=\left[(6.4 x-1)^{2}+(5.4 x-2)^{3}\right]^{2}

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Answered 2 years ago
Answered 2 years ago
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f(x)=[(6.4x1)2+(5.4x2)3]2Differentiate both sides with respect to xf(x)=ddx[(6.4x1)2+(5.4x2)3]2Apply the chain rulef(x)=2[(6.4x1)2+(5.4x2)3]21ddx[(6.4x1)2+(5.4x2)3]Therefore,f(x)=2[(6.4x1)2+(5.4x2)3][2(6.4x1)(6.4)+3(5.4x2)2(5.4)]Simplifyf(x)=2[(6.4x1)2+(5.4x2)3][12.8(6.4x1)+16.2(5.4x2)2]f(x)=[25.6(6.4x1)+32.4(5.4x2)2][(6.4x1)2+(5.4x2)3]\begin{gathered} f\left( x \right) = {\left[ {{{\left( {6.4x - 1} \right)}^2} + {{\left( {5.4x - 2} \right)}^3}} \right]^2} \\ \textcolor{#4257b2}{{\text{Differentiate both sides with respect to }}x} \\ f'\left( x \right) = \frac{d}{{dx}}{\left[ {{{\left( {6.4x - 1} \right)}^2} + {{\left( {5.4x - 2} \right)}^3}} \right]^2} \\ \textcolor{#4257b2}{ {\text{Apply the chain rule}}} \\ f'\left( x \right) = 2{\left[ {{{\left( {6.4x - 1} \right)}^2} + {{\left( {5.4x - 2} \right)}^3}} \right]^{2 - 1}}\frac{d}{{dx}}\left[ {{{\left( {6.4x - 1} \right)}^2} + {{\left( {5.4x - 2} \right)}^3}} \right] \\ \textcolor{#4257b2}{ {\text{Therefore}}{\text{,}}} \\ f'\left( x \right) = 2\left[ {{{\left( {6.4x - 1} \right)}^2} + {{\left( {5.4x - 2} \right)}^3}} \right]\left[ {2\left( {6.4x - 1} \right)\left( {6.4} \right) + 3{{\left( {5.4x - 2} \right)}^2}\left( {5.4} \right)} \right] \\ \textcolor{#4257b2}{ {\text{Simplify}}} \\ f'\left( x \right) = 2\left[ {{{\left( {6.4x - 1} \right)}^2} + {{\left( {5.4x - 2} \right)}^3}} \right]\left[ {12.8\left( {6.4x - 1} \right) + 16.2{{\left( {5.4x - 2} \right)}^2}} \right] \\ f'\left( x \right) = \left[ {25.6\left( {6.4x - 1} \right) + 32.4{{\left( {5.4x - 2} \right)}^2}} \right]\left[ {{{\left( {6.4x - 1} \right)}^2} + {{\left( {5.4x - 2} \right)}^3}} \right] \\ \end{gathered}

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