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Question

# Calculate the grams or milliliters of solute needed to prepare the following solutions:a. 50.0 mL of a 5.0 %(m / v) KCl} solutionb. 1250 mL of a $4.0 \%(\mathrm{~m} / \mathrm{v}) \mathrm{NH}_4 \mathrm{Cl}$ solutionc. 250 .mL of a 10.0 %(v / v) acetic acid solution

Solution

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a) $V(KCl)=50ml$ (solution) $m/V(KCl)=5\%$ By knowing the pattern:

$m/V=\dfrac{mass \ of \ solute}{volume \ of \ solution}\cdot100\%$

we will calculate what is unknown to us:

$mass \ of \ solute=\dfrac{5}{100}\cdot50=\boxed{2,5g}$

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