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Question

Calculate the grams or milliliters of solute needed to prepare the following solutions:

a. 50.0 mL of a 5.0 %(m / v) KCl} solution

b. 1250 mL of a 4.0%( m/v)NH4Cl4.0 \%(\mathrm{~m} / \mathrm{v}) \mathrm{NH}_4 \mathrm{Cl} solution

c. 250 .mL of a 10.0 %(v / v) acetic acid solution

Solution

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Answered 2 years ago
Answered 2 years ago
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a) V(KCl)=50mlV(KCl)=50ml (solution) m/V(KCl)=5%m/V(KCl)=5\% By knowing the pattern:

m/V=mass of solutevolume of solution100%m/V=\dfrac{mass \ of \ solute}{volume \ of \ solution}\cdot100\%

we will calculate what is unknown to us:

mass of solute=510050=2,5gmass \ of \ solute=\dfrac{5}{100}\cdot50=\boxed{2,5g}

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