## Related questions with answers

Question

Calculate the increase in length of a zinc rod $50.0 \mathrm{~m}$ long at $15.0{\degree} \mathrm{C}$ when it is heated to $130.0{\degree} \mathrm{C}$.

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 2$\textbf{Given:}$

$l=50 \text{ m}$

$T_1=15 ^\circ \text{C}$

$T_2=130 ^\circ \text{C}$

$\alpha= 2.6 \times 10^{-5} \dfrac{\text{ }}{^\circ\text{C}}$

The change in the length of the material under the influence of the change in temperature is given by the formula:

$\Delta l=\alpha \cdot l \cdot \Delta T$

By including the given data in the formula we get:

$\begin{align*} \Delta l&=\alpha \cdot l \cdot (T_2-T_1) \\ &=2.6 \times 10^{-5} \cdot 50 \cdot (130-15)\\ &\boxed{\Delta l=0.15 \text{ m} } \end{align*}$

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Recommended textbook solutions

#### Physics for Scientists and Engineers: A Strategic Approach with Modern Physics

4th Edition•ISBN: 9780133942651 (8 more)Randall D. Knight3,508 solutions

#### Applied Physics

11th Edition•ISBN: 9780134159386Dale Ewen, Erik Gundersen, Neill Schurter3,468 solutions

#### Mathematical Methods in the Physical Sciences

3rd Edition•ISBN: 9780471198260 (1 more)Mary L. Boas3,355 solutions

#### Fundamentals of Physics

10th Edition•ISBN: 9781118230718 (3 more)David Halliday, Jearl Walker, Robert Resnick8,971 solutions

## More related questions

1/4

1/7