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Question

Calculate the inductive reactance, XLX_\text{L}, of a 50-μH50\text{-}\mu\text{H} coil at the following frequencies: a. f=60 Hzf=60\text{ Hz}. b. f=10 kHzf=10\text{ kHz}. c. f=500 kHzf=500\text{ kHz}. d. f=3.8 MHzf=3.8\text{ MHz}.

Solution

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Answered 1 year ago
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Here given that we have a 50 μH50~\mu\text{H} inductor we need to calculate the value of inductive reactance for the given values of frequencies.

The opposition to the flow of current provided by an inductor is the inductive reactance of that inductor. The value of inductive reactance is given by the following equation:

XL=2πfL(1)X_\text{L}=2\pi\cdot f\cdot L\tag1

Here,

XLX_\text{L}\to Inductive reactance ((Ohms).).

ff\to Frequency of alternating current ((Hertz).).

LL\to Inductance ((Henry).).

So, using the above equation we can find the value of inductive reactance for different values of frequencies.

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