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Question

Calculate the value of gmg_{m} for a BJT biased at IC=0.5mA.I_{C}=0.5 \mathrm{mA}.

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According to Eq.(7.62),

gm=ICVT=0.5 mA25 mV=20 mA/V\begin{align*} g_m &=\dfrac{I_C}{V_T}\\&=\dfrac{0.5\mathrm{~mA}}{25 \mathrm{~mV}}\\&=\boxed{\color{#c34632}{20\mathrm{~mA/V} }} \end{align*}

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