Question

# Germanium can be used to measure the energy of incident photons. Consider a 660-keV gamma ray emitted from ${ }^{137} \mathrm{C}$. Given that the band gap in germanium is $0.72 \mathrm{eV}$, how many electron-hole pairs can be generated as this gamma ray travels through germanium?

Solution

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Information given in this part:

• $E_\gamma = 660\mathrm{~keV}$, gamma ray energy
• $E_g = 0.72\mathrm{~eV}$, energy gap in germanium

We have to determine how many electron-hole pairs can this gamma ray create.