Question

Germanium can be used to measure the energy of incident photons. Consider a 660-keV gamma ray emitted from 137C{ }^{137} \mathrm{C}. Given that the band gap in germanium is 0.72eV0.72 \mathrm{eV}, how many electron-hole pairs can be generated as this gamma ray travels through germanium?

Solution

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Answered 1 year ago
Answered 1 year ago
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Information given in this part:

  • Eγ=660 keVE_\gamma = 660\mathrm{~keV}, gamma ray energy
  • Eg=0.72 eVE_g = 0.72\mathrm{~eV}, energy gap in germanium

We have to determine how many electron-hole pairs can this gamma ray create.

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