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Charge is distributed within a solid sphere of radius r0r_0 in such a way that the charge density is a function of the radial position within the sphere of the form: ρE(r)=ρ0(r/r0)\rho_{\mathrm{E}}(r)=\rho_0\left(r / r_0\right). If the total charge within the sphere is QQ (and positive), what is the electric field everywhere within the sphere in terms of Q,r0Q, r_0, and the radial position rr ?

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Suppose we have a solid sphere, with radius of r0r_0 and charge density of ρE(r)=ρ0(rr0)\rho_E(r)=\rho_0 \left(\frac{r}{r_0}\right), we need to find the electric field inside and out side the sphere , first, inside the sphere, draw a Gauss surface (sphere) inside the original sphere with radius of rr as shown in the following figure:

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