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Question

Check each data set for outliers.

a. 14,18,27,26,19,13,5,2514,18,27,26,19,13,5,25 b. 112,157,192,116,153,129,131112,157,192,116,153,129,131

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(a) 14, 18, 27, 26, 19, 13, 5, 25 \text{\textcolor{#4257b2}{\textbf{(a) 14, 18, 27, 26, 19, 13, 5, 25 }}}

To find the outliers, we execute following steps :

Step 1 : \textbf{Step 1 : } Computing median :

First we arrange the data-set in order from lowest to highest :

5 , 13 , 14 , 18 , 19 , 25 , 26 , 275\text{ , }13\text{ , }14\text{ , }18\text{ , }19\text{ , }25\text{ , }26\text{ , }27

number of values=n=8\text{number of values} = n = 8

Since number of values are even hence the median is mean of (n2)th\left(\dfrac{n}{2}\right)^{th} and (n+22)th\left(\dfrac{n+2}{2}\right)^{th} value. Hence median of data set is mean of 4th4^{th} and 5th5^{th} value.

median=(18+192)median=18.5\begin{align*} \text{median} &= \left(\dfrac{18+19}{2}\right)\\ \text{median} &= 18.5 \end{align*}

Step 2 : \textbf{Step 2 : } Computing Q1Q_{1} :

Q1Q_{1} for a given data set is the median of values less than median of that data set.

The new data-set formed using values less than median (=18.5)(=18.5) is :

5 , 13 , 14 , 185\text{ , }13\text{ , }14\text{ , }18

number of values in new data set=n=4\text{number of values in new data set} = n = 4

Since number of values are even hence the median is mean of (n2)th\left(\dfrac{n}{2}\right)^{th} and (n+22)th\left(\dfrac{n+2}{2}\right)^{th} value. Hence median of data set is mean of 2nd2^{nd} and 3rd3^{rd} value.

Q1=(13+142)Q1=13.5\begin{align*} Q_{1} &= \left(\dfrac{13+14}{2}\right)\\ Q_{1} &= 13.5 \end{align*}

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