Question

Chlorine consists of the following isotopes:

 Isotope  Isotopic  Fractional  Chlorine-35  Mass (amu)  Abundance  Chlorine-37 34.968850.75771\begin{array}{lll}\text { Isotope } & \text { Isotopic } & \text { Fractional } \\ \text { Chlorine-35 } & \text { Mass (amu) } & \text { Abundance } \\ \text { Chlorine-37 } & 34.96885 & 0.75771 \\ \end{array}

What is the atomic mass of chlorine?

Solution

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From the problem we have next information:

m(Chlorine-35)=34,96885  amu\text{m}(\text{Chlorine-35})= 34,96885 \; \text{amu}

m(Chlorine-37)=36,96590  amu\text{m}(\text{Chlorine-37})= 36,96590 \; \text{amu}

X(Chlorine-35)=0,75771\text{X}(\text{Chlorine-35})=0,75771

X(Chlorine-37)=0,24229\text{X}(\text{Chlorine-37})= 0,24229

We need to calculate what is the atomic mass of chlorine.

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