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Question

Compute each. Assume the values of the variables are restricted so that the expressions are defined.

(n1)!(n+1)!\frac { ( n - 1 ) ! } { ( n + 1 ) ! }

Solution

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(n1)!(n+1)!=(n1)!(n+1)n(n1)!=1n(n+1)\dfrac{(n-1)!}{(n+1)!}=\dfrac{(n-1)!}{(n+1)*n*(n-1)!}=\dfrac{1}{n*(n+1)}

Use the fact that (n+1)!=(n+1)n(n-1)! to help with the simplification.

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