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Question

Consider a two-state quantum system with a Hamiltonian

H(E100E2)H \doteq\left(\begin{array}{cc} E_1 & 0 \\ 0 & E_2 \end{array}\right)

Another physical observable AA is described by the operator

A=(0aa0)A=\left(\begin{array}{ll} 0 & a \\ a & 0 \end{array}\right)

where aa is real and positive. Let the initial state of the system be ψ(0)=a1|\psi(0)\rangle=\left|a_1\right\rangle, where a1\left|a_1\right\rangle is the eigenstate corresponding to the larger of the two possible eigenvalues of AA. What is the frequency of oscillation (i.e., the Bohr frequency) of the expectation value of AA ?

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In this problem, we are given a two-state system with a Hamiltonian

H=[E100E2]H=\begin{bmatrix}E_1&0\\0&E_2\end{bmatrix}

Let's consider an observable given as

A=[0aa0]A=\begin{bmatrix}0&a\\a&0\end{bmatrix}

If the system is in the state a1>\ket {a_1} we want to know the Bohr frequency of the expectation value of A.

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