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Question

Consider the diffusion of oxygen through a low-density polyethylene (LDPE) sheet 15 mm thick. The pressures of oxygen at the two faces are 2000 kPa and 150 kPa, which are maintained constant. Assuming conditions of steady state, what is the diffusion flux [in (cm3STP)/cm2s]\left.\left(\mathrm{cm}^{3} \mathrm{STP}\right) / \mathrm{cm}^{2} \cdot \mathrm{s}\right] at 298 K?

Solution

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We will employ the following equation:

J=PmΔPΔx\begin{align*} J=\dfrac{P_m\Delta P}{\Delta x} \end{align*}

We need to look up the value for PmP_m from table 14.614.6 on page 572572 which results in Pm=2.2×1013P_m=2.2\times10^{-13}. Additionally, we'll need the pressures to be in Pascals vice kPa

J=(2.2×1013)(2000000150000)1.5=2.7×106 cm3STPcm2s\begin{align*} J&=\dfrac{(2.2\times10^{-13})(2000000-150000)}{1.5}\\\\ &=\boxed{2.7\times10^{-6}\dfrac{\text{ cm}^3\text{STP}}{\text{cm}^2\text{s}}} \end{align*}

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