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Consider the following curves on the given intervals. a. Write the integral that gives the area of the surface generated when the curve is revolved about the given axis. b. Use a calculator or software to approximate the surface area. y=(2x+3)2y=(2 x+3)^{2}, for 0x10 \leq x \leq 1; about the y-axis

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Let x=g(y)x = g(y) be greater of equal to 00 with continuous first derivative on interval [c,d][c, d]. The area of the surface generated when the the graph of gg on the interval [c,d][c, d] is revolved about the yy-axis is

S=cd2πg(y)1+g(y)2dyS = \int_c^d 2\pi g(y) \sqrt{1 + g'(y)^2 } \,dy

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