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Consider the following equilibrium process at 686 degree C: CO2 (g) + H2O (g) >=> CO (g) + H2O (g) The equilibrium concentrations of the reacting species are [CO] = 0.050 M, [H2] = 0.045 M, [CO2] = 0.086 M, and [H2O] = 0.040 M. (a) Calculate Kc for the reaction at 686°C. (b) If we add CO2 to increase its concentration to 0.50 mol/L, what will the concentrations of all the gases be when equilibrium is reestablished?
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Answered 5 months ago
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We have a reversible reaction with equilibrium concentrations of
= 0.050
= 0.045
= 0.086
= 0.040 .
We need to find the following
(a) at this temperature.
(b) equilibrium composition if we we make [] = 0.50
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