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Question

Consider the function f defined by f(x)=5xtanx,0x<π2f(x)=5 x-\tan x, 0 \leq x<\frac{\pi}{2}.

a. Find the equation of the tangent to the graph of ff at x=π4x=\frac{\pi}{4}.

b. There is a point A on the graph of f where the normal to the graph is vertical. Determine the coordinates of A.

Solution

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Answered 1 year ago
Answered 1 year ago
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(a) Differentiate f(x)f(x) with respect to xx to evaluate f(x)f'(x).

f(x)=ddx[f(x)]=ddx(5xtanx)=ddx(5x)ddx(tanx)Difference rule=5ddx(x)ddx(tanx)Constant Multiple rule=5x11sec2x=5sec2x\begin{aligned}f'(x)&=\dfrac{d}{dx}[f(x)]\\&=\dfrac{d}{dx}(5x-\tan{x})\\&=\dfrac{d}{dx}(5x)-\dfrac{d}{dx}(\tan{x})&&\color{#4257b2}\text{Difference rule}\\&=5\dfrac{d}{dx}(x)-\dfrac{d}{dx}(\tan{x})&&\color{#4257b2}\text{Constant Multiple rule}\\&=5x^{1-1}-\sec^2{x}\\&=5-\sec^2{x}\end{aligned}

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