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Question

Consider the function f(x,y)=xy+x+y+100f(x, y)=x y+x+y+100 subject to the constraint xy=4x y=4. Solve the system in part (a) to verify that (x,y)=(2,2)(x, y)=(-2,-2) and (x,y)=(2,2)(x, y)=(2,2) are solutions.

Solution

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Answered 1 year ago
Answered 1 year ago

To solve the system, first express xx and yy from the first two equations:

x=y=1λ1\begin{align*} & x = y = \dfrac{1}{\lambda-1} \end{align*}

Since x=yx= y, the third equation implies:

x2=4    x=±2x^2 = 4 \implies x = \pm 2

Hence, the two solutions to the system are (2,2)(2,2) and (2,2)(-2,-2).

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