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Question

Consider the function f(x)=exx1f(x)=\frac{e^{x}}{x-1}. Find the equation of the tangent at the point where x = 2.

Solution

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Answered 2 years ago
Answered 2 years ago
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Find the yy-coordinate of the point at x=2x=2

f(2)=e221=e2\begin{aligned} f(2) &= \dfrac{ e^2}{2-1 } = e^2 \end{aligned}

The point is (2,e2)(2, e^2)

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