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Question

Consider the plane ax+by+cz=d, where a, b, c, and d are all positive. Use previous problem to show that the volume of the tetrahedron cut from the first octant by this plane is dD/(3a2+b2+c2)d D /\left(3 \sqrt{a^2+b^2+c^2}\right), where D is the area of that part of the plane in the first octant.

Solution

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Answered 2 years ago
Answered 2 years ago
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We can proved using the Gauss's Divergence Theorem that the volume of the solid enclosed by the surface SS is given by:

V(S)=13SFndSV(S)=\dfrac{1}{3}\iint_{S}{\bf F}\cdot{\bf n}dS

Where F=(x,y,z){\bf F}=(x,y,z).

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