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Question

Construct a (7, 3) code in which every nonzero codeword has Hamming weight at least 4.

Solution

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Answered 2 years ago
Answered 2 years ago
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We will construct (7,3)(7,3) code generated by the standard generator matrix

G=(100110101011100011011).G=\begin{pmatrix} 1 & 0 & 0 & 1 & 1 & 0 & 1\\ 0 & 1 & 0 & 1 & 1 & 1 & 0\\ 0 & 0 & 1 & 1 & 0 & 1 & 1 \end{pmatrix}.

Message words of (7,3)(7,3) code are:

{000, 001, 010, 011, 100, 101, 110, 111}.\{ 000, \ 001, \ 010, \ 011, \ 100, \ 101, \ 110, \ 111 \} .

Multiplying message words with GG we get appropriate codewords:

{0000000,0011011,0101110,1001101,0110101,1100011,1010110,1111000}.\begin{align*} \{ &0000000, 0011011, 0101110, 1001101, \\ &0110101, 1100011, 1010110, 1111000 \}. \end{align*}

We see that every nonzero codeword has Hamming weight at least 4.

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