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Question

Customers in a Bank A bank has a drive-through service. The number of customers arriving during a 1515-minute period is distributed as shown. Find the mean. variance, and standard deviation for the distribution.

Number of customersX01234ProbabilityP(X)0.120.200.310.250.12\begin{array}{l|ccccc} \textbf{Number of customers} X & 0 & 1 & 2 & 3 & 4 \\ \hline \textbf{Probability} P(X) & 0.12 & 0.20 & 0.31 & 0.25 & 0.12 \end{array}

Solution

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The mean μ\mu of a random variable with a discrete probability distribution is the sum of the products of the outcomes XX and their corresponding probabilities P(X)P(X).

μ=X1P(X1)X2P(X2)...XnP(Xn)=XP(X)\mu=X_1\cdot P(X_1)\cdot X_2\cdot P(X_2)\cdot...\cdot X_n\cdot P(X_n)=\sum X\cdot P(X)

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