Question

# (d) Which of the graphs in Figure 19.73 represents the current in circuit 1 as a function of time?

Solution

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The capacitor is initially uncharged which means the electric field contributed by the capacitor to the net electric field inside the wire is zero. When the circuit is connected and the current running in the wires for a second, the charges accumulate on the plates of the capacitor then the fringe electric field of the capacitor will contribute to the net electric field inside the wire leading to decrease the current in the wire because it acts in the opposite direction of the conventional current.

After this little time, the light of the bulb will decrease until disappearing. So, the current decreases after connected the circuit with time and the correct figure is ,$\textbf{(A)}$ where the current decays with the time.

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