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Decide whether the functions defined as follows are probability density functions on the indicated intervals. If not, tell why. f(x)=2x2f(x)=2 x^{2}; [-1, 1]

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From the definition:

The function ff is a probability density function of a random variable xx in the interval [a,b][a,b] if :

1.f(x)0 for all x in interval[a,b]2.abf(x)dx=1.\begin{align*} &1.f(x)\geq0 \text{ for all x in interval} [a,b]\\ &2.\int_{a}^{b} f(x)\,dx=1. \end{align*}

We need to check these to conditions.

First condition:

f(x)=2x2f(x)=2\cdot x^{2}

On the interval [1,1][-1,1], x20x^{2}\geq0, any number squared is positive number, so this condition is fulfilled.

Second condition:

112x2dx=211x2dx=2x2+12+111=2x3311=2x331=21332133=2323=23+23=43\begin{align*} \int_{-1}^{1} 2x^{2}\,dx&=2\int_{-1}^{1} x^2\,dx\\ &=2\frac{x^{2+1}}{2+1}\bigg|_{-1}^{1}\\ &=2\frac{x^{3}}{3}\bigg|_{-1}^{1}\\ &=\frac{2\,x^{3}}{3}\bigg|_{-1}^{}\\ &=\frac{2\cdot 1^{3}}{3}-\frac{2\cdot -1^{3}}{3}\\ &=\frac{2}{3}-\frac{-2}{3}\\ &=\frac{2}{3}+\frac{2}{3}\\ &=\frac{4}{3}\\ \end{align*}

Second condition is not fulfilled.

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