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Question

Describe the method you would use to solve the following equation for 0x<3600^{\circ} \leq x<360^{\circ}.

sin2x=sinx\sin ^{2} x=\sin x.

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We need to describe the method that we will use to solve

sin2x=sinx\sin^2x=\sin x

for 0°x<360°0\degree\leq x<360\degree.

What methods can we use to solve the trigonometric equation?

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