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Determine the pH\mathrm{pH} for the following solutions:

(a) 5.0×105 M HNO35.0 \times 10^{-5}~M\mathrm{~HNO}_3
(b) 2.0×106 M KOH2.0 \times 10^{-6}~M\mathrm{~KOH}

Solution

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Answered 2 years ago
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In this task, we need to calculate pH of solution.

If we have a strong acid or base (100 % ionized), the concentration of H+^+ and OH^- ions is equal to the concentration of acid and base, respectively.

Relationship between H+^+ and OH^- concentration is ion product constant for water KwK_w.

For water dissociation:

H2OH++OH\text{H$_2$O} \rightleftharpoons \text{H$^+$} + \text{OH$^–$}

the KwK_w is:

Kw=[H+][OH]K_w=[\text{H$^+$}][\text{OH$^–$}]

At 25 °\degreeC, the value of KwK_w is:

Kw=11014 mol2/dm6K_w=1 \cdot 10^{-14} \mathrm{~mol^2/dm^6}

The pH of solution can be calculated using the formula:

pH=log([H+])pH=-\log([\text{H$^+$}])

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