Question

Determine the number of moles of N\mathrm{N} atoms in 43.5 g43.5 \mathrm{~g} of Mg(NO3)2\mathrm{Mg}\left(\mathrm{NO}_3\right)_2

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Given: Mass of Mg(NO3)2\mathrm{Mg(NO_{3})_{2}} = 43.5 g

(1) First, calculate for the molar mass of Mg(NO3)2\mathrm{Mg(NO_{3})_{2}} as shown below:

Molar mass = Mg+N2+O6\text{Molar mass = Mg} + \mathrm{N_{2}} + \mathrm{O_{6}}

Molar mass = 24.31 g + 2 (14.01 g) + 6 (16.00 g)\text{Molar mass = 24.31 g + 2 (14.01 g) + 6 (16.00 g)}

Molar mass = 148.3 g\text{Molar mass = 148.3 g}

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