Determine the volume of $\mathrm{Cl}_2$ gas at $\mathrm{STP}$ that will react with $1.00$ mole of $\mathrm{Na}$ solid to produce $\mathrm{NaCl}$ according to the equation,

$2 \mathrm{Na}(s)+\mathrm{Cl}_2(g) \longrightarrow 2 \mathrm{NaCl}(s)$

a) $22.4 \mathrm{~L}$ d) $11.2 \mathrm{~L}$ b) $44.8 \mathrm{~L}$ e) $30.6 \mathrm{~L}$ c) $15.3 \mathrm{~L}$

Solution

VerifiedOur task is to determine the **volume of chlorine gas at STP** in the given reaction.

A **balanced chemical equation** possesses the same number of atoms and each element on each reaction side. The **mole ratio** of reactant to reaction product is determined by the coefficients of the reactant and product in a balanced chemical equation.

The **equation of ideal gas** elaborates on the physical properties of gases by using gas laws to relate pressure, volume, the number of moles, and the temperature to one another.

**STP** is the Standard Temperature and Pressure, where the normal **temperature** is 273.15 K, and the standard **pressure** is 1 atm.