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Question

Determine the volume to the nearest cubic unit. cone r=20 in. h=25 in.

Solution

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The volume VV of a cone or a pyramid is the product of the base area BB and the height hh.

V=13BhV=\frac{1}{3}Bh

where BB is the base area and hh is the height of the cone or pyramid.

Given:

d=20  inr=d2=202=10  ind=20 \text{ \ in} \Rightarrow r=\frac{d}{2}=\frac{20}{2}=10 \text{ \ in}

h=25  inh=25 \text{ \ in}

Area of the circle is

A=πr2=π(d2)2A=\pi r^2=\pi \left(\frac{d}{2}\right)^2

where rr is the radius of the circle and dd is the diameter.

So,

B=πr2=π(10)2=100π  in2=100×3.14314  in2B=\pi r^2=\pi (10)^2=100 \pi \text{ \ in}^2 =100 \times 3.14 \approx 314 \text{ \ in}^2

Hence,

V=13Bh=13×314×25  in3=2617  in3V=\frac{1}{3}Bh=\frac{1}{3} \times 314 \times 25 \text{ \ in}^3=2617 \text{ \ in}^3

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