## Related questions with answers

Determine whether a normal sampling distribution can be used. If can be used, test the claim about the difference between two population proportions

$p _ { 1 }$

and

$p _ { 2 }$

at the level of significance

$\alpha$

. Assume the samples are random and independent. Claim:

$p _ { 1 } < p _ { 2 }; \alpha = 0.05$

. Sample statistics:

$x _ { 1 } = 471, n _ { 1 } = 785$

and

$x _ { 2 } = 372, n _ { 2 } = 465$

Solution

VerifiedGiven:

$p_1<p_2$

$\alpha=0.05$

$x_1=471$

$n_1=785$

$x_2=372$

$n=2=465$

(a) The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis and the alternative hypothesis state the opposite of each other. The null hypothesis needs to contain the value mentioned in the claim.

$H_0:p_1\geq p_2$

$H_a:p_1<p_2$

If the alternative hypothesis contains $<$, then the test is left-tailed.

If the alternative hypothesis contains $>$, then the test is right-tailed.

If the alternative hypothesis contains $\neq$, then the test is two-tailed. Left-tailed test

Determine the sample proportions. The sample proportion is the number of successes divided by the sample size:

$\hat{p}_1=\dfrac{x_1}{n_1}=\dfrac{471}{785}=0.6$

$\hat{p}_2=\dfrac{x_2}{n_2}=\dfrac{372}{465}=0.8$

$\overline{p}=\dfrac{x_1+x_2}{n_1+n_2}=\dfrac{471+372}{785+465}=0.6744$

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