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Question

Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. -If f(x) = sin²(2x), then f’(x) = 2(sin 2x)(cos 2x).

Solution

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f(x)=sin2(2x)f(x) = sin^2(2x)

f(x)=2sin(2x)21ddxsin(2x)f'(x) = 2sin(2x)^{2-1} \cdot \dfrac{d}{dx} sin(2x)

=2sin(2x)cos(2x)ddx(2x)= 2sin(2x) \cdot cos(2x) \cdot \dfrac{d}{dx}(2x)

=4sin(2x)cos(2x)= 4sin(2x) cos(2x)

We can see from the chain rule, that the derivative shown for the function is missing an extra factor of 2 from the inner-most funciton (2x)

Also the derivative can be simplified by the sin double angle identity.

4sin(2x)cos(2x)=2sin(4x)4sin(2x)cos(2x) = 2sin(4x)

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